12m^2+132m=0

Solution for 12m^2+132m=0 equation:

12m^2+132m=0

a = 12; b = 132; c = 0;
Δ = b2-4ac
Δ = 1322-4·12·0
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(132)-132}{2*12}=\frac{-264}{24}
=-11
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(132)+132}{2*12}=\frac{0}{24}
=0
$